4x^2-15x+40=0

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Solution for 4x^2-15x+40=0 equation:


Simplifying
4x2 + -15x + 40 = 0

Reorder the terms:
40 + -15x + 4x2 = 0

Solving
40 + -15x + 4x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
4 the coefficient of the squared term: 

Divide each side by '4'.
10 + -3.75x + x2 = 0

Move the constant term to the right:

Add '-10' to each side of the equation.
10 + -3.75x + -10 + x2 = 0 + -10

Reorder the terms:
10 + -10 + -3.75x + x2 = 0 + -10

Combine like terms: 10 + -10 = 0
0 + -3.75x + x2 = 0 + -10
-3.75x + x2 = 0 + -10

Combine like terms: 0 + -10 = -10
-3.75x + x2 = -10

The x term is -3.75x.  Take half its coefficient (-1.875).
Square it (3.515625) and add it to both sides.

Add '3.515625' to each side of the equation.
-3.75x + 3.515625 + x2 = -10 + 3.515625

Reorder the terms:
3.515625 + -3.75x + x2 = -10 + 3.515625

Combine like terms: -10 + 3.515625 = -6.484375
3.515625 + -3.75x + x2 = -6.484375

Factor a perfect square on the left side:
(x + -1.875)(x + -1.875) = -6.484375

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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